dict generator question
grflanagan at gmail.com
Fri Sep 19 14:37:44 CEST 2008
Boris Borcic wrote:
> Gerard flanagan wrote:
>> George Sakkis wrote:
>>> Note that this works correctly only if the versions are already sorted
>>> by major version.
>> Yes, I should have mentioned it. Here's a fuller example below.
>> There's maybe better ways of sorting version numbers, but this is what
>> I do.
> Indeed, your sort takes George's objection too litterally, what's needed
> for a correct endresult is only that major versions be grouped together,
> and this is most simply obtained by sorting the input data in (default)
> string order, is it not ?
Yes, I see what you mean - the fact that a default sort orders "1.10"
before "1.9" doesn't actually matter for the required result.
>> datadict = \
>> dict((k, len(list(g))) for k,g in groupby(data, lambda s: s[:3]))
And, s[:3] is wrong. So:
datadict = \
dict((k, len(list(g))) for k,g in groupby(data, lambda s:
should work, I hope.
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