Question about sorted in Python 3.0rc1
hniksic at xemacs.org
Mon Sep 22 15:29:53 CEST 2008
josh logan <dear.jay.logan at gmail.com> writes:
> sorted(P) # throws TypeError: unorderable types Player() < Player()
> The sorted function works when I define __lt__.
> I must be misreading the documentation, because I read for the
> documentation __cmp__ that it is called if none of the other rich
> comparison functions are defined.
> Is this a bug in Python 3.0rc1, or am I missing something?
What documentation are you referring to, exactly? The whole __cmp__
thing was supposed to be removed from Python 3, so mention of it
sounds like a documentation bug.
> Secondly, say that we suddenly need another sorting order, where we
> want to sort by decreasing score and then by DECREASING last name
> (instead of increasing last name, defined above). Now that the
> comparison function argument is taken away from the sorted builtin,
> how do we accomplish this with the "key" parameter?
By calling sort twice on the sequence:
lst.sort(key=lambda x: x.score)
lst.sort(key=lambda x: x.last_name, reverse=True)
As much as I like the key argument, I believe it was a mistake to
remove cmp, simply because it was the more general mechanism.
Emulating cmp with key is possible, but it requires creating a bunch
of objects for each sort. (I'm aware that list.sort caches the
calculated keys, but it still has to create as many of them as there
are list items.)
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