python syntax for conditional is unfortunate

Aaron "Castironpi" Brady castironpi at gmail.com
Thu Sep 25 05:16:49 CEST 2008


On Sep 24, 9:49 pm, Asun Friere <afri... at yahoo.co.uk> wrote:
> On Sep 25, 11:57 am, "Aaron \"Castironpi\" Brady"
>
> <castiro... at gmail.com> wrote:
> > On Sep 24, 8:40 pm, Asun Friere <afri... at yahoo.co.uk> wrote:
> > > ... I think
> > > your last version ('%d thing%s' % (i, 's' if i != 1 else '')), holding
> > > all variables for placeholders in the tuple, is better. It's certainly
> > > more readible.
>
> > It's a different answer if you have 'things is/are'.  '%d thing%s %s'%
> > ( ( i, )+ ( 's', 'are' ) if i!= 1 else ( '', 'is' ) ).  Or excluding
> > prepositional phrases and subordinate clauses, '%d thing%s'% ( i, 's
> > are' if i!= 1 else ' is' ).
>
> Forgive me for being dull, my caffeine levels have not yet optimal,
> but I don't follow.  Both the solutions you propose do put all the
> placeholder variables in the tuple.  Or are you saying it no longer
> remains readible?
>
> BTW you repeated my mistake with the first scraplet of code.

Ah yes.  Maybe the order of precedence can undergo a change in the
future.  ... Though talk about backwards incompatible.  They were two
options if you have a verb with your noun, which would need a
conditional too.



More information about the Python-list mailing list