how to find position of dictionary values

lee san82moon at gmail.com
Mon Sep 1 10:44:32 CEST 2008


On Sep 1, 1:21 pm, Alexandru Palade
<alexandru.pal... at sellerengine.com> wrote:
> lookfor = 'dfsdf'
> for item, value in kev.items():
>         if lookfor in value:
>                 print item
>                 print value.index(lookfor)
>                 break   # assuming you only want one result
>
> You can also skip the 'if' verification in which case you need to catch
> ValueError exception in case there is no such entry in the current list.
>
> Hope it helps.
>
> lee wrote:
> > hi,
> > i have a dictionary as follows :
> > kev :  {'phno': ['dgsd', 'gsdg', 'dfsdf', 'g'], 'email': ['dg',
> > 'sgsd', 'sdfsdf', 'gdf'], 'name': ['ds', 'dsg', 'dsfds', 'fgdf'],
> > 'address': ['sdg', 'dsgsdg', 'sdf', 'dfg']}
>
> > if user is enters the 3rd item of key phno, ie "dfsdf" in my dict,
> > how can i find it is the third  item in the internal list of phno of
> > that dictionary?  thanks you.
> > --
> >http://mail.python.org/mailman/listinfo/python-list

hi, thank u your solution is exactly wat i wanted  :)



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