Handling NameError in a list gracefully
JesseAldridge at gmail.com
Mon Apr 20 22:48:15 CEST 2009
On Apr 20, 3:46 pm, Chris Rebert <c... at rebertia.com> wrote:
> On Mon, Apr 20, 2009 at 1:36 PM, Jesse Aldridge <JesseAldri... at gmail.com> wrote:
> > from my_paths import *
> > def get_selected_paths():
> > return [home, desktop, project1, project2]
> > -------
> > So I have a function like this which returns a list containing a bunch
> > of variables. The real list has around 50 entries. Occasionally I'll
> > remove a variable from my_paths and cause get_selected_paths to throw
> > a NameError. For example, say I delete the "project1" variable from
> > my_paths; now I'll get a NameError when I call get_selected_paths.
> > So everything that depends on the get_selected_paths function is
> > crashing. I am wondering if there is an easy way to just ignore the
> > variable if it's not found. So, in the example case I would want to
> > somehow handle the exception in a way that I end up returning just
> > [home, desktop, project2].
> > Yes, I realize there are a number of ways to reimplement this, but I'm
> > wanting to get it working with minimal changes to the code. Any
> > suggestions?
> def get_selected_paths():
> variables = "home desktop project1 project2".split()
> vals = 
> for var in variables:
> vals.append(getattr(my_paths, var))
> except AttributeError:
> return vals
> I have a blog:http://blog.rebertia.com
Hey, that's even better. Thanks.
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