Best way to extract from regex in if statement

[Jon Clements]

On 4 Apr, 02:14, bwgoudey <bwgou... at gmail.com> wrote:
> I have a lot of if/elif cases based on regular expressions that I'm using to
> filter stdin and using print to stdout. Often I want to print something
> matched within the regular expression and the moment I've got a lot of cases
> like:
>
> ...
> elif re.match("^DATASET:\s*(.+) ", line):
>         m=re.match("^DATASET:\s*(.+) ", line)
>         print m.group(1))
>
> which is ugly because of the duplication but I can't think of a nicer of way
> of doing this that will allow for a lot of these sorts of cases. Any
> suggestions?
> --
> View this message in context:http://www.nabble.com/Best-way-to-extract-from-regex-in-if-statement-...
> Sent from the Python - python-list mailing list archive at Nabble.com.

How about something like:

your_regexes = [
    re.compile('rx1'),
    re.compile('rx2'),
    # etc....
]

for line in lines:
    for rx in your_regexes:
        m = rx.match(line)
        if m:
            print m.group(1)
            break # if only the first matching regex is required,
otherwise leave black for all

Untested, but seems to make sense

hth,

Jon