How to find out in which module an instance of a class is created?
mail at johannes-janssen.de
Mon Aug 10 23:51:59 CEST 2009
Christian Heimes schrieb:
> Johannes Janssen wrote:
>> > class A(object):
>> > def __init__(self, mod=__name__):
>> > self.mod = mod
>> .... won't work. In this case mod would always be "foo".
> You have to inspect the stack in order to get the module of the
> caller. The implementation of warnings.warn() gives you some examples
> how to get the module name.
Thanks for the quick and very helpful reply. Basically just copying from
warnings.warn(), I came up with this:
def __init__(self, mod=None):
if mod is None:
self.mod = sys._getframe(1).f_globals['__name__']
self.mod = mod
In warnings.warn() they used try around sys._getframe(1). As far as I
understand what is done in warnings, there it is not sure what object
caused the warning and therefore it is not sure whether you can or
cannot use sys._getframe(1). Though in my case it should be quite clear.
Can I be sure that my code will always work?
More information about the Python-list