matching patterns after regex?

[Martin]

On Aug 12, 10:29 pm, Mark Lawrence <breamore... at yahoo.co.uk> wrote:
> Bernard wrote:
> > On 12 août, 12:43, Martin <mdeka... at gmail.com> wrote:
> >> On Aug 12, 1:42 pm, Martin <mdeka... at gmail.com> wrote:
>
> >>> On Aug 12, 1:23 pm, Steven D'Aprano <st... at REMOVE-THIS-
> >>> cybersource.com.au> wrote:
> >>>> On Wed, 12 Aug 2009 05:12:22 -0700, Martin wrote:
> >>>>> I tried
> >>>>> re.findall((\w+COORDINATE).*\s+VALUE\s+=\s([\d\.\w-]+),s)
> >>>> You need to put quotes around strings.
> >>>> In this case, because you're using regular expressions, you should use a
> >>>> raw string:
> >>>> re.findall(r"(\w+COORDINATE).*\s+VALUE\s+=\s([\d\.\w-]+)",s)
> >>>> will probably work.
> >>>> --
> >>>> Steven
> >>> Thanks I see.
> >>> so I tried it and if I use it as it is, it matches the first instance:
> >>> I
> >>> n [594]: re.findall(r"(\w+COORDINATE).*\s+VALUE\s+=\s([\d\.\w-]+)",s)
> >>> Out[594]: [('NORTHBOUNDINGCOORDINATE', '1')]
> >>> So I adjusted the first part of the regex, on the basis I could sub
> >>> NORTH for SOUTH etc.
> >>> In [595]: re.findall(r"(NORTHBOUNDINGCOORDINATE).*\s+VALUE\s+=\s([\d\.
> >>> \w-]+)",s)
> >>> Out[595]: [('NORTHBOUNDINGCOORDINATE', '1')]
> >>> But in both cases it doesn't return the decimal value rather the value
> >>> that comes after NUM_VAL = , rather than VALUE = ?
> >> I think I kind of got that to work...but I am clearly not quite
> >> understanding how it works as I tried to use it again to match
> >> something else.
>
> >> In this case I want to print the values 0.000000 and 2223901.039333
> >> from a string like this...
>
> >> YDim=1200\n\t\tUpperLeftPointMtrs=(0.000000,2223901.039333)\n\t\t
>
> >> I tried which I though was matching the statement and printing the
> >> decimal number after the equals sign??
>
> >> re.findall(r"(\w+UpperLeftPointMtrs)*=\s([\d\.\w-]+)", s)
>
> >> where s is the string
>
> >> Many thanks for the help
>
> > You have to do it with 2 matches in the same regex:
>
> > regex = r"UpperLeftPointMtrs=\(([\d\.]+),([\d\.]+)"
>
> > The first match  is before the , and the second one is after the , :)
>
> > You should probably learn how to play with regexes.
> > I personnaly use a visual tool called RX Toolkit[1] that comes with
> > Komodo IDE.
>
> > [1]http://docs.activestate.com/komodo/4.4/regex.html
>
> Haven't tried it myself but how about this?http://re-try.appspot.com/
>
> --
> Kindest regards.
>
> Mark Lawrence.

Thanks Mark and Bernard. I have managed to get it working and I
appreciate the help with understanding the syntax. The web links are
also very useful, I'll give them a go.

Martin