flatten a list of list
steve at REMOVE-THIS-cybersource.com.au
Sun Aug 16 13:31:57 CEST 2009
On Sun, 16 Aug 2009 06:59:52 -0400, Chris Rebert wrote:
>> Surely that's going to be O(N**2)?
> The OP asked for "simple", not "best", "most proper", or "fastest". My
> comment was intended to mean that the code was marginally *simpler*, not
Fair enough, but he also asked for Pythonic, and while some people might
argue that "terrible performance" is Pythonic, I hope you wouldn't be one
of them! :)
If it soothes your ruffled sense of honour *wink*, I think your solution
with itertools.chain is probably the best so far.
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