Protecting against callbacks queuing up?
Esben von Buchwald
find.mig at paa.google
Sun Aug 23 20:14:24 EDT 2009
Hello
I'm using Python for S60 1.9.7 on my Nokia phone.
I've made a program that gets input from an accelerometer sensor, and
then calculates some stuff and displays the result.
The sensor framework API does a callback to a function defined by me,
every time new data is available.
The problem is, that sometimes, the calculations may take longer than
others, but if the callback is called before the first calculation is
done, it seems like it's queuing up all the callbacks, and execute them
sequentially, afterwards.
What I need, is to simply ignore the callback, if the previous call
hasn't finished it's operations before it's called again.
I thought that this code would do the trick, but it obviously doesn't
help at all, and i can't understand why...
def doCallback(self):
if self.process_busy==False:
self.process_busy=True
self.data_callback()
self.process_busy=False
doCallback is defined as a callback function for the accelerometer
instance, and data_callback does some calculations and show them on the
display of the phone.
What to do? Thanks...
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