How to write replace string for object which will be substituted? [regexp]

[MRAB]

ryniek90 wrote:
> Hi.
> I started learning regexp, and some things goes well, but most of them 
> still not.
> 
> I've got problem with some regexp. Better post code here:
> 
> "
>  >>> import re
>  >>> mail = '\nname at mail.com\nname1 [at] mail [dot] com\nname2 [$at$] 
> mail [$dot$] com\n'
>  >>> mail
> '\nname at mail.com\nname1 [at] mail [dot] com\nname2 [$at$] mail [$dot$] 
> com\n'
>  >>> print mail
> 
> name at mail.com
> name1 [at] mail [dot] com
> name2 [$at$] mail [$dot$] com
> 
>  >>> maail = re.sub('^\n|$\n', '', mail)
>  >>> print maail
> name at mail.com
> name1 [at] mail [dot] com
> name2 [$at$] mail [$dot$] com
>  >>> maail = re.sub(' ', '', maail)
>  >>> print maail
> name at mail.com
> name1[at]mail[dot]com
> name2[$at$]mail[$dot$]com
>  >>> maail = re.sub('\[at\]|\[\$at\$\]', '@', maail)
>  >>> print maail
> name at mail.com
> name1 at mail[dot]com
> name2 at mail[$dot$]com
>  >>> maail = re.sub('\[dot\]|\[\$dot\$\]', '.', maail)
>  >>> print maail
> name at mail.com
> name1 at mail.com
> name2 at mail.com
>  >>> #How must i write the replace string to replace all this regexp's 
> with just ONE command, in string 'mail' ?
>  >>> maail = re.sub('^\n|$\n| |\[at\]|\[\$at\$\]|\[dot\]|\[\$dot\$\]', 
> *?*, mail)
> "
> 
> How must i write that replace pattern (look at question mark), to maek 
> that substituion work? I didn't saw anything helpful while reading Re 
> doc and HowTo (from Python Doc). I tried with 'MatchObject.group()' but 
> something gone wrong - didn't wrote it right.
> Is there more user friendly HowTo for Python Re, than this?
> 
> I'm new to programming an regexp, sorry for inconvenience.
> 
I don't think you can do it in one regex, nor would I want to. Just use
the string's replace() method.

 >>> mail = '\nname at mail.com\nname1 [at] mail [dot] com\nname2 [$at$] 
mail [$dot$] com\n'
 >>> mail
'\nname at mail.com\nname1 [at] mail [dot] com\nname2 [$at$] mail [$dot$] 
com\n'
 >>> print mail

name at mail.com
name1 [at] mail [dot] com
name2 [$at$] mail [$dot$] com

 >>> maail = mail.strip()
name at mail.com
name1 [at] mail [dot] com
name2 [$at$] mail [$dot$] com

 >>> maail = maail.replace(' ', '')
 >>> print maail
name at mail.com
name1[at]mail[dot]com
name2[$at$]mail[$dot$]com
 >>> maail = maail.replace('[at]', '@').replace('[$at$]', '@')
 >>> print maail
name at mail.com
name1 at mail[dot]com
name2 at mail[$dot$]com
 >>> maail = maail.replace('[dot]', '.').replace('[$dot$]', '.')
 >>> print maail
name at mail.com
name1 at mail.com
name2 at mail.com