Splitting a string into substrings of equal size
Simon Forman
sajmikins at gmail.com
Sun Aug 16 15:36:20 EDT 2009
On Aug 14, 8:22 pm, candide <cand... at free.invalid> wrote:
> Suppose you need to split a string into substrings of a given size (except
> possibly the last substring). I make the hypothesis the first slice is at the
> end of the string.
> A typical example is provided by formatting a decimal string with thousands
> separator.
>
> What is the pythonic way to do this ?
>
> For my part, i reach to this rather complicated code:
>
> # ----------------------
>
> def comaSep(z,k=3, sep=','):
> z=z[::-1]
> x=[z[k*i:k*(i+1)][::-1] for i in range(1+(len(z)-1)/k)][::-1]
> return sep.join(x)
>
> # Test
> for z in ["75096042068045", "509", "12024", "7", "2009"]:
> print z+" --> ", comaSep(z)
>
> # ----------------------
>
> outputting :
>
> 75096042068045 --> 75,096,042,068,045
> 509 --> 509
> 12024 --> 12,024
> 7 --> 7
> 2009 --> 2,009
>
> Thanks
FWIW:
def chunks(s, length=3):
stop = len(s)
start = stop - length
while start > 0:
yield s[start:stop]
stop, start = start, start - length
yield s[:stop]
s = '1234567890'
print ','.join(reversed(list(chunks(s))))
# prints '1,234,567,890'
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