Got a single octet from socket, what to do ?

[mudit tuli]

Stephen, thanks a lot for the reply. This worked for me.
I had a look at the struct module earlier but ignored it due to lack of
examples, I'll look more into it.

Mudit

On Sat, Dec 5, 2009 at 8:17 AM, Stephen Hansen <apt.shansen at gmail.com>wrote:

> On Fri, Dec 4, 2009 at 6:39 PM, mudit tuli <mudit.tuli at gmail.com> wrote:
>
>> I am very new to Python and started getting to know socket programming
>> recently.
>> Made a socket server, which receives a "Single Octet"(treated as a single
>> 8-bit integer field) from a client.
>> But I am not sure what to do with this "Single Octet" and how to decode it
>> into a long integer, so that I can make use of it .
>> Any Ideas ?
>>
>>
> Check out the "struct" module for low-level byte-stream protocols.
>
> >>> my_byte = '\x0c'
> >>> print struct.unpack("<B", my_byte)
> (12, )
>
> That would convert the byte string "my_byte" containing a single byte into
> a tuple according to the format string passed.. In this case, < specifies
> network/big-endian byte order, and "B" specifies that the the message
> contains a single unsigned byte as a number. The tuple will thus contain a
> 12.
>
> There's some other more direct ways you can approach the problem, but
> struct is really IMHO best and using it early in your protocol is the best
> practice.
>
> --S
>
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