console command to get the path of a function

[mattia]

Il Sun, 20 Dec 2009 13:53:18 +0100, Irmen de Jong ha scritto:

> On 12/20/2009 1:45 PM, mattia wrote:
>> Hi all, is there a way in the python shell to list the path of a
>> library function (in order to look at the source code?).
>>
>> Thanks, Mattia
> 
> something like this?
> 
>  >>> import inspect
>  >>> import os
>  >>> inspect.getsourcefile(os.path.split)
> 'C:\\Python26\\lib\\ntpath.py'
>  >>> print inspect.getsource(os.path.split)
> def split(p):
>      """Split a pathname.
>   ...
>   ...
> 
> 
> --irmen

Ok, but how can I retrieve information about built-in functions (if any)?

>>> inspect.getsourcefile(itertools.product)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "C:\Python31\lib\inspect.py", line 439, in getsourcefile
    filename = getfile(object)
  File "C:\Python31\lib\inspect.py", line 406, in getfile
    raise TypeError('arg is a built-in class')
TypeError: arg is a built-in class