casevh at gmail.com
Mon Feb 2 03:20:15 CET 2009
On Feb 1, 1:04 pm, Mensanator <mensana... at aol.com> wrote:
> On Feb 1, 2:27 am, casevh <cas... at gmail.com> wrote:
> > On Jan 31, 9:36 pm, "Tim Roberts" <t.robe... at cqu.edu.au> wrote:
> > > Actually, all I'm interested in is whether the 100 digit numbers have an exact integral root, or not. At the moment, because of accuracy concerns, I'm doing something like
> > > for root in powersp:
> > > nroot = round(bignum**(1.0/root))
> > > if bignum==long(nroot)**root:
> > > .........
> > > which is probably very inefficient, but I can't see anything better.....
> > > Tim
> > Take a look at gmpy and the is_power function. I think it will do
> > exactly what you want.
> And the root function will give you the root AND tell you whether
> it was an integral root:
> >>> gmpy.root(a,13)
> (mpz(3221), 0)
> In this case, it wasn't.
I think the original poster wants to know if a large number has an
exact integral root for any exponent. is_power will give you an answer
to that question but won't tell you what the root or exponent is. Once
you know that the number is a perfect power, you can root to find the
> > casevh
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