Extracting file from zip archive in Python 2.6.1
Brandon Taylor
btaylordesign at gmail.com
Tue Feb 3 02:31:24 EST 2009
Hello everyone,
I'm having an issue specifying the path for extracting files from
a .zip archive. In my method, I have:
zip_file.extract(zip_name + '/' + thumbnail_image, thumbnail_path)
What is happening is that the extract method is creating a folder with
the name of 'zip_name' and extracting the files to it. Example:
if 'thumbnail_path' is 'images/inventory/thumbnails/'
extract is creating: 'images/inventory/thumbnails/test1/'
and saving the files out. How can I set the path to be exactly:
'images/inventory/thumbnails' ?
TIA,
Brandon
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