Using while loop and if statement to tell if a binary has an odd or even number of 1's.

todpose at hotmail.com todpose at hotmail.com
Wed Feb 4 20:23:46 EST 2009


By "binary representation", I mean a byte of 0s and 1s. Example: 00000101
Also, I'm interested in only using while loop and if statement to accomplish this task.
Thanks.> Date: Wed, 4 Feb 2009 17:18:25 -0800> Subject: Re: Using while loop and if statement to tell if a binary has an odd or even number of 1's.> From: clp2 at rebertia.com> To: todpose at hotmail.com> CC: python-list at python.org> > On Wed, Feb 4, 2009 at 5:02 PM, todpose at hotmail.com <todpose at hotmail.com> wrote:> > Using while loop and if statement, I'm trying to get Python to tell me> > whether there are even or odd number of 1's in a binary representation.> > For example, if I give Python a 00000111, then I want it to say that the> > binary representation given has an odd number of 1's.> > If I give it 00010111, then it will tell me that there is an even number of> > 1's.> > I'd appreciate any suggestion.> > Please define "binary representation". Do you mean a sequence of> bytes, an integer, a string of 0s and 1s, or something else entirely?> > If it's a string of 0s and 1s, then:> is_even = zerosones.count('1') % 2 == 0> > For an integer:> is_even = bin(the_int)[2:].count('1') % 2 == 0> > For the others, I don't know offhand.> > Cheers,> Chris> > -- > Follow the path of the Iguana...> http://rebertia.com
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