Use list name as string
vincent at vincentdavis.net
Thu Feb 5 04:37:04 CET 2009
Jervis Whitley wrote "Although you should really solve your problem by
thinking about it
from a completely different angle, maybe subclassing your datatype and
adding a 'name'
attribute ? I'm sure some of the others here have suggested that already."
That is beyond my current knowledge. Any suggestions for reading about this?
On Wed, Feb 4, 2009 at 8:24 PM, Jervis Whitley <jervisau at gmail.com> wrote:
> On Thu, Feb 5, 2009 at 3:57 AM, Vincent Davis <vincent at vincentdavis.net>
> > Sorry for not being clear
> > I would have something like this
> > x = [1, 2, 3,5 ,6 ,9,234]
> > Then
> > def savedata(dataname): ..........
> > savedata(x)
> > this would save a to a file called x.csv This is my problem, getting the
> > name to be x.csv which is the same as the name of the list.
> > and the data in the file would be
> > 1,2,3,5,6,9,234 this parts works
> It sounds like you would _really_ like to attach a name to this list of
> How about this terrible example to solve your problem.
> x = dict(x=[1,2,3,5,6,9,234])
> def savedata(dataname):
> # extract the first key(name) and value(data) from the dataname data
> name, data = dataname.items()
> except AttributeError:
> raise TypeError("Expecting a datatype that declares method 'items'
> # we could catch other exceptions here but I wont (like empty items).
> now you have your name and your data variable.
> This way you don't declare your variable name when calling savedata
> but when you
> create your variable.
> Although you should really solve your problem by thinking about it
> from a completely
> different angle, maybe subclassing your datatype and adding a 'name'
> attribute ? I'm
> sure some of the others here have suggested that already.
-------------- next part --------------
An HTML attachment was scrubbed...
More information about the Python-list