Using while loop and if statement to tell if a binary has an odd or even number of 1's.
Tim Rowe
digitig at gmail.com
Thu Feb 5 11:10:31 CET 2009
2009/2/5 Duncan Booth <duncan.booth at invalid.invalid>:
> Mark Dickinson <dickinsm at gmail.com> wrote:
>
>> def count_set_bits(n):
>> # make sure we include an if, to
>> # satisfy OP's requirements:
>> if n < 0:
>> raise ValueError
>> count = 0
>> while n:
>> count += 1
>> n &= n-1
>> return count
>>
>> is_even = count_set_bits(the_int) % 2 == 0
>>
>> ...but anyone submitting this as a homework
>> solution had better be prepared to explain why
>> it works.
>>
>
> I remember a programming exercise when I was an undergraduate and anyone
> who *didn't* use that trick got marked down for writing inefficient code.
Is adding and a modulus *really^ more efficient than flipping a bool
as I suggested? I think I'd want to see measurements!
--
Tim Rowe
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