flexible find and replace ?

[bearophileHUGS at lycos.com]

OdarR:

> how would you do a clever find and replace, where the value replacing
> the tag is changing on each occurence ?
> ".......TAG............TAG................TAG..........TAG....."
> is replaced by this :
> ".......REPL01............REPL02................REPL03..........REPL04..."


You may use something like this (tested) replacing XXXXXXXXXXXX with
the correct re function:

import re

def replacer(mobj):
    replacer.counter += 1
    return "REPL%02d" % replacer.counter
replacer.counter = 0

print re.XXXXXXXXXXXX("TAG", replacer, s1)

(If you have more than 99 replacements it will use more than two
digits.)

Bye,
bearophile