Pythonic way to determine if one char of many in a string

[John Machin]

On Feb 19, 6:47 pm, Dennis Lee Bieber <wlfr... at ix.netcom.com> wrote:
> On Wed, 18 Feb 2009 21:22:45 +0100, Peter Otten <__pete... at web.de>
> declaimed the following in comp.lang.python:
>
> > Steve Holden wrote:
>
> > > Jervis Whitley wrote:
> > >>> What happens when you have hundreds of megabytes, I don't know.
>
> > >> I hope I never have to test a word that is hundreds of megabytes long
> > >> for a vowel :)
>
> > > I see you don't speak German ;-)
>
> > I tried to come up with a funny way to point out that you're a fool.
>
> > But because I'm German I failed.
>
>         Yeah... the proper language to bemoan is Welsh <G>
>
> Where "w" is vowel <G>

Better bemoaned is Czech which can go on and on using only L and R as
"sonorant consonants" instead of vowels.