How to find the beginning of last line of a big text file ?
python.list at tim.thechases.com
Thu Jan 1 19:03:46 CET 2009
Sebastian Bassi wrote:
> On Thu, Jan 1, 2009 at 2:19 PM, Barak, Ron <Ron.Barak at lsi.com> wrote:
>> I have a very big text file: I need to find the place where the last line
>> begins (namely, the offset of the one-before-the-last '\n' + 1).
>> Could you suggest a way to do that without getting all the file into memory
>> (as I said, it's a big file), or heaving to readline() all lines (ditto) ?
> for line in open(filename):
> lastline = line
> print "the lastline is: %s",%lastline
> This will read all the lines, but line by line, so you will never have
> the whole file in memory.
> There may be more eficient ways to do this, like using the itertools.
I think the OP wanted to do it without having to touch each line
in the file. The following should do the trick, returning both
the offset in the file, and that last line's content.
from os import stat
def last_line(fname, estimated_line_size=1024):
assert estimated_line_size > 0
file_size = stat(fname).st_size
if not file_size: return 0, ""
f = file(fname, 'rb')
f.seek(-1, 2) # grab the last character
if f.read(1) == '\n': # a "proper" text file
file_size -= 1
offset = file_size
content = ""
while offset >= 0 and '\n' not in content:
offset -= estimated_line_size
if offset < 0:
estimated_line_size += offset # back it off
offset = 0
block = f.read(estimated_line_size)
content = block + content
loc = content.rfind('\n') + 1 # after the newline
return offset + loc, content[loc:]
offset, line = last_line('some_file.txt')
print "[%r] was found at offset %i" % (line, offset)
In theory, it should even handle "malformed" text-files that
don't end in a newline. There might be some odd edge-cases that
I missed, but I think I caught most of them.
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