Pass by reference

alex goretoy aleksandr.goretoy at gmail.com
Sat Jan 3 03:05:49 CET 2009


You are correct, terminology is a must. In order to stay on the same page.
And yes, it;s not technically by ref. but it works for me at the moment.

I was doing this in my code:
l={"user":"asdf","pass":"goog"}
d= {
    "login_url":"http://example.com/login",
    "user":l["user"],
    "pass":l["pass"]

}
and it wouldn't work. So I had to do some research on how to make it work.
passing a mutable object resolved my problem. Thank you for correcting me.
-A


On Thu, Jan 1, 2009 at 6:22 PM, Terry Reedy <tjreedy at udel.edu> wrote:

> alex goretoy wrote:
>
>> I recently conquered this pass by ref thing. This is how I did it.
>>
>
> What you did was to pass a mutable object and mutate it.  Absolutely
> standard practice in Python.  I am glad you learned it, but also learning
> and using the standard terminology will also help.  Hope you enjoy Python
> too.
>
> tjr
>
>
> --
> http://mail.python.org/mailman/listinfo/python-list
>



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