list iteration if statement

Mensanator mensanator at aol.com
Sat Jan 3 04:23:17 CET 2009


On Jan 2, 8:43�pm, "alex goretoy" <aleksandr.gore... at gmail.com> wrote:
> rather, how do I suppress the output of the list with all None in it?
>
> >>> l=[['3'], ['0', '4'], ['0', '1'], ['0']]
> >>> v=[]
> >>> [[v.append(j)for j in i if j != "0"] for i in l]
>
> [[None], [None], [None], []]
>
> >>> v
> ['39', '32', '1']
>

Assign it to something.

>>> ignore_me = [[v.append(j)for j in i if j != "0"] for i in l]
>>> v
['3', '4', '1']



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