Simple CGI-XMLRPC failure

[Mike MacHenry]

I figured it was some kind of bug. Must be either a bug with my
version of either the library (most likely) or perhaps some weird
environment setting that I have set incorrectly (also likely). How can
I figure out which version of SimpleXMLRPCServer I'm running? Do you
run Ubuntu by any chance? If you which version?

Does anyone know of any environment settings I could look into on
Apache or Python?

-mike

On Mon, Jan 12, 2009 at 9:02 PM, Jeff McNeil <jeff at jmcneil.net> wrote:
> On Jan 12, 12:40 pm, "Mike MacHenry" <dski... at ccs.neu.edu> wrote:
>> I am having a difficult time understanding why my very simple
>> CGI-XMLRPC test isn't working. I created a server to export two
>> functions, the built-in function "pow" and my own identity function
>> "i". I run a script to call both of them and the "pow" work fine but
>> the "i" gives me an error that says my XMLRPC server doesn't support
>> than name. Here is the code for both files and the output:
>>
>> #!/usr/bin/env python
>> #This file is /usr/lib/cgi-bin/roundwarerpc.py
>> from SimpleXMLRPCServer import CGIXMLRPCRequestHandler
>> def i(x):
>>         return x
>> server = CGIXMLRPCRequestHandler()
>> server.register_function(pow)
>> server.register_function(i)
>> server.handle_request()
>>
>> #!/usr/bin/env python
>> #This file is ~/test.py
>> import xmlrpclib
>> server = xmlrpclib.ServerProxy("http://localhost/cgi-bin/roundwarerpc.py")
>> print server.pow(2,3)
>> print server.i(10)
>>
>> #This is the STDOUT and STDERR when running ~/test.py
>> dskippy at dskippy-laptop:$ python test.py 8
>> Traceback (most recent call last):
>>   File "test.py", line 4, in <module>
>>     print server.test(10)
>>   File "/usr/lib/python2.5/xmlrpclib.py", line 1147, in __call__
>>     return self.__send(self.__name, args)
>>   File "/usr/lib/python2.5/xmlrpclib.py", line 1437, in __request
>>     verbose=self.__verbose
>>   File "/usr/lib/python2.5/xmlrpclib.py", line 1201, in request
>>     return self._parse_response(h.getfile(), sock)
>>   File "/usr/lib/python2.5/xmlrpclib.py", line 1340, in _parse_response
>>     return u.close()
>>   File "/usr/lib/python2.5/xmlrpclib.py", line 787, in close
>>     raise Fault(**self._stack[0])
>> xmlrpclib.Fault: <Fault 1: '<type \'exceptions.Exception\'>:method "i"
>> is not supported'>
>>
>> Does anyone know what might be wrong with this?
>>
>> Thanks for the help,
>> -mike
>>
>> p.s.
>> Python 2.5.2 (r252:60911, Jul 31 2008, 17:28:52)
>> [GCC 4.2.3 (Ubuntu 4.2.3-2ubuntu7)] on linux2
>> Server version Apache/2.2.8 (Ubuntu)
>> Server built: Jun 25 2008 13:54:13
>
> I copied your code verbatim and I don't have any issues with it at
> all. Same version of Python, same version of Apache.
>
> In SimpleXMLRPCServer.py, register_function adds directly to a
> self.funcs dictionary, so an instance variable of the same name
> shouldn't hurt anything.  That exception is only raised when a
> self.funcs lookup raises a KeyError unless you're registering an
> instance.
>
> --
> http://mail.python.org/mailman/listinfo/python-list
>