function argument dependent on another function argument?
steve at REMOVE-THIS-cybersource.com.au
Sun Jan 18 16:26:25 CET 2009
On Sun, 18 Jan 2009 06:19:03 -0800, Reckoner wrote:
> I would like to do:
> def foo(self,x,y=self.a)
> where the default value for y=self.a. Since this is not possible, I wind
> up doing
> def foo(self,x,y=None)
> if not y:
> but that seems kind of clumsy.
It's also incorrect, because if you pass y=0 as an argument, or any other
false value, it will be replaced by self.a.
> Is there a better way to do this?
def foo(self, x, y=None):
if y is None:
y = self.a
I don't find that clumsy in the least. I find it perfectly readable and a
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