function argument dependent on another function argument?

Aaron Brady castironpi at gmail.com
Sun Jan 18 15:41:31 CET 2009


On Jan 18, 8:19 am, Reckoner <recko... at gmail.com> wrote:
> I  would like to do:
>
> def foo(self,x,y=self.a)
>
> where the default value for y=self.a. Since this is not possible, I
> wind up doing
>
> def foo(self,x,y=None)
>   if not y:
>     y=self.a
>
> but that seems kind of clumsy.
>
> Is there a better way to do this?
>
> Thanks in advance

No.  The only alternative is really niche and probably not what you
want.  You'd use a decorator (which I don't have, btw):

@defval( y= selfattrget( 'a' ) )
def foo( self, x, y ).






More information about the Python-list mailing list