regex question on .findall and \b
python.list at tim.thechases.com
Thu Jul 2 19:17:22 CEST 2009
Ethan Furman wrote:
> My closest to successfull attempt:
> Python 2.5.4 (r254:67916, Dec 23 2008, 15:10:54) [MSC v.1310 32 bit (Intel)]
> Type "copyright", "credits" or "license" for more information.
> IPython 0.9.1 -- An enhanced Interactive Python.
> In : re.findall('\d+','this is test a3 attempt 79')
> Out: ['3', '79']
> What I really want in just the 79, as a3 is not a decimal number, but
> when I add the \b word boundaries I get:
> In : re.findall('\b\d+\b','this is test a3 attempt 79')
> Out: 
> What am I missing?
The sneaky detail that the regexp should be in a raw string
(always a good practice), not a cooked string:
The "\d" isn't a valid character-expansion, so python leaves it
alone. However, I believe the "\b" is a control character, so
your actual string ends up something like:
>>> print repr('\b\d+\b')
>>> print repr(r'\b\d+\b')
the first of which doesn't match your target string, as you might
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