Looking for a slick way to classify relationship between two numbers, without tons of if/else
ben.welsh at gmail.com
Tue Jul 7 03:25:13 CEST 2009
In my application, I'd like to have a function that compares two values,
either of which may be null, and then classify the result depending on
whether one is higher or lower than the other.
I find myself writing something clunky like this, and I'm curious whether
anyone might know a more elegant way for parsing this out.
def compare(a, b):
if not a and not b:
return "No data"
if a == 0 and b == 0:
return "Never had"
if a == b:
return "Stayed the same"
elif a < b:
elif a > b and b > 0:
return "Lost Some"
elif a > b and b == 0:
return "Lost All"
If there's some obvious way to search for this solution online, feel free to
slap me with that. I tried digging around on Google and couldn't come up
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