missing 'xor' Boolean operator

[Dr. Phillip M. Feldman]

I did initially ask for an infix xor operator, but eventually gave up on
this.  I like the first of your two one-line solutions below; this is clean
and easy to understand.  Thanks!  I'd still like to be able to write an
expression like '(a and b) xor (c and d) xor (e and f)', but it looks as
though that can't be done.



<snip>

Well, that's not exactly what you originally asked for.  But it's
still a one-liner:

def xor(*args): return bool(sum(map(bool, args)) % 2)

or perhaps

def xor(*args): return bool(len(filter(None, args)) & 1)
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