Hello
Dave Angel
davea at ieee.org
Thu Jul 9 10:04:23 EDT 2009
You could pick a much better title. And apparently you started a new
thread with this one. When responding to an existing message, you ought
to reply-all to the existing message, rather than starting a new thread.
Tanmoy wrote:
>> Hello ,
>> When i==0 you append an empty list to arr, so arr[i] is arr[0]. No
>> problem.
>>
>> When i==10 you append another empty list to arr, so arr[i] is arr[10].
>> Index error because there's no arr[10], only arr[0] and arr[1].
>>
>> Thanks for your prompt reply...
>>
>> How can i pass this problem
>>
>> You could try appending to arr[-1] instead.
>>
>
> Better still:
>
> ...
> row = []
> for j in range(0,1001,1):
> row.append(i+j)
> arr.append(row)
> ...
> I tried both the ways... the only thing is its not coming like 0 10
> 20.......1000 . Its coming like 0,1,2,........1000.....Any answer to the
> problem.
> Thanks
> Tanmoy Mukherjee
>
>
If you want the row to count by 10's you have to build it that way. You
have the arguments to the ranges backwards. Try:
arr=[]
for i in range(1001):
row = []
for j in range(0,1010,10):
row.append(i+j)
arr.append(row)
Coincidentally, once you reverse them, the original problem would go
away. But this is better anyway, as it makes it clear what's
happening. You are building 1001 rows, each containing non-contiguous
numbers.
DaveA
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