missing 'xor' Boolean operator

[Paul Rubin]

Anthony Tolle <anthony.tolle at gmail.com> writes:
> def xor(*operands):
>     if operands:
>         operands = list(operands)
>         a = bool(operands.pop(0))
>         while operands:
>             b = bool(operands.pop(0))
>             if a:
>                 if b:
>                     a = False
>             elif b:
>                 a = True
>         return a
>     return False

Among other things, that uses quadratic time!  Why do you want to keep
popping items from that list instead of iterating through it anyway?

Anyway, I think you wrote something close to this:

def xor(*operands):
   r = False
   for x in operands:
      r = (r != bool(x))
   return r

or in map-reduce style:

    from operator import ne
    def xor(*operands):
       return reduce(ne, map(bool, operands), False)