can it be shorter?
steve at REMOVE-THIS-cybersource.com.au
Sat Jun 6 18:38:27 CEST 2009
On Sun, 07 Jun 2009 00:21:45 +0800, tsangpo wrote:
> "kj" <no.email at please.post> 写入消息 news:h0e3p9$85t
$1 at reader1.panix.com...
>> In <h0e0oi$1es2$1 at adenine.netfront.net> "tsangpo"
>> <tsangpo.newsgroup at gmail.com> writes:
>>>I want to ensure that the url ends with a '/', now I have to do thisa
>>>url = url + '' if url[-1] == '/' else '/'
>>>Is there a better way?
>> It's a pity that in python regexes are an "extra", as it were.
>> Otherwise I'd propose:
>> url = re.sub("/?$", "/", url)
>> kynn (lowest-of-the-low python noob)
> look nice, but:
>>>> re.sub('/?$/', '/', 'aaabbb')
> has no effect. what a pity.
That's because you're doing it wrong. You've added an extra slash: you're
asking the regex engine to match a backslash *after* the end of the
string. Obviously that will never match.
>>> re.sub('/?$/', '/', 'aaabbb') # extra /
>>> re.sub('/?$', '/', 'aaabbb') # no extra /
But before you get too excited, see my previous post: the regex solution
is more than ten times slower than test-and-concatenate.
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