Measuring Fractal Dimension ?
Charles Yeomans
charles at declareSub.com
Wed Jun 17 13:37:32 CEST 2009
On Jun 17, 2009, at 2:04 AM, Paul Rubin wrote:
> Jaime Fernandez del Rio <jaime.frio at gmail.com> writes:
>> I am pretty sure that a continuous sequence of
>> curves that converges to a continuous curve, will do so uniformly.
>
> I think a typical example of a curve that's continuous but not
> uniformly continuous is
>
> f(t) = sin(1/t), defined when t > 0
>
> It is continuous at every t>0 but wiggles violently as you get closer
> to t=0. You wouldn't be able to approximate it by sampling a finite
> number of points. A sequence like
>
> g_n(t) = sin((1+1/n)/ t) for n=1,2,...
>
> obviously converges to f, but not uniformly. On a closed interval,
> any continuous function is uniformly continuous.
Isn't (-∞, ∞) closed?
Charles Yeomans
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