python-2.6.2 Exception: TypeError: "'NoneType' object is not callable" in ignored

[Dave Angel]

Poor Yorick wrote:
> <div class="moz-text-flowed" style="font-family: -moz-fixed">The 
> following code produces an error (python-2.6.2).  Either of the following
> eliminates the error:
>
>     . assign something besides mod1 (the newly-created module) to d1
>
>     . remove the call to shelve.open
>
> Why is there an error produced in the first place?  What is the 
> interaction
> between d1, mod1, and shelve about?  This code runs without error in 
> python-3.1
>
>     $ cat test1.py
>     import test2
>     newmodule = test2.load()
>
>     $ cat test2.py
>
>     import imp
>     import shelve
>
>     def load():
>             text='import test2\n'
>             text += '''print('hello from test3')\n'''
>             code = compile(text,'<fake>', 'exec')
>             mod1 = imp.new_module('newmodule')
>
>             newdict = mod1.__dict__
>             #newdict = {}
>
>             exec(code,newdict)
>             mod1
>             mode = mod1
>             d1['unique'] = mod1
>             #d1['unique'] = ''
>             return mod1
>
>     print('hello from test2')
>     d1 = {}
>     cache = shelve.open('persist')
>
>     $ python2.6 test1.py
>     hello from test2
>     hello from test3
>     Exception TypeError: "'NoneType' object is not callable" in  ignored
>     Exception TypeError: "'NoneType' object is not callable" in  ignored
>
You don't need all those lines to trigger these exception messages.  All 
you need in  test1.py is the import statement.  And in test2.py:

import shelve
cache = shelve.open('persist')

To cure it, just close the cache:

cache.close()

I don't have any idea what the exception means, but this seems like a 
logical thing, to close it.