Determining if a function is a method of a class within a decorator
Carl Banks
pavlovevidence at gmail.com
Tue Jun 30 20:50:20 EDT 2009
On Jun 29, 6:01 pm, David Hirschfield <dav... at ilm.com> wrote:
> So is there
> a pattern I can follow that will allow me to determine whether the
> objects I'm given are plain functions or belong to a class?
>
> Thanks in advance,
class HomemadeUnboundMethod(object):
def __init__(self,func):
self.func = func
def __call__(self,*args,**kwargs):
print "is a function: %s" % self.func.func_name
return self.func(*args,**kwargs)
def __get__(self,obj,owner):
return HomemadeBoundMethod(obj,self.func)
class HomemadeBoundMethod(object):
def __init__(self,obj,func):
self.obj = obj
self.func = func
def __call__(self,*args,**kwargs):
print "is a method: %s" % self.func.func_name
return self.func(self.obj,*args,**kwargs)
class A(object):
@HomemadeUnboundMethod
def method(self): pass
@HomemadeUnboundMethod
def function(): pass
A().method()
function()
Just override the __call__ functions to do what you want the decorated
function to do. There are other little improvements you might make
(account for the owner parameter of __get__ for instance) but you get
the idea.
Carl Banks
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