You could do something like this so that every process will know if
the file "belongs" to it without prior coordination, it means a lot
of redundant hashing though.
In [36]: import md5
In [37]: pool = 11
In [38]: process = 5
In [39]: [f for f in glob.glob('*') if int(md5.md5(f).hexdigest(),16)
% pool == process ]
Out[39]: