unziping a file in python..

[Luis Zarrabeitia]

Quoting MRAB <google at mrabarnett.plus.com>:
> Steven D'Aprano wrote:
> > A quick and dirty solution would be something like this:
> > 
> > zf = zipfile.ZipFile('Archive.zip')
> > for name in zf.namelist():
> >     open(name, 'w').write(zf.read(name))
> > 
> You might want to specify an output folder (and the data might be binary
> too):
> 
> zf = zipfile.ZipFile('Archive.zip')
> for name in zf.namelist():
>      open(os.path.join(output_folder, name), 'wb').write(zf.read(name))
> 

Question here... wouldn't you also need to create all the intermediate folders
from "output_folder" to "output_folder/name" (assuming that 'name' has several
path parts in it)? Is there any elegant way to do it? 

(is there any way to make os.mkdir behave like mkdir -p?)

-- 
Luis Zarrabeitia
Facultad de Matemática y Computación, UH
http://profesores.matcom.uh.cu/~kyrie

 Participe en Universidad 2010, del 8 al 12 de febrero de 2010
 La Habana, Cuba 
 http://www.universidad2010.cu