Emulate a printf() C-statement in Python???

Chris Rebert clp2 at rebertia.com
Thu Mar 19 13:52:53 CET 2009


On Thu, Mar 19, 2009 at 5:43 AM, Mr. Z <noone at xspambellsouth.net> wrote:
> I'm trying emulate a printf() c statement that does, for example
>
> char* name="Chris";
> int age=30;
> printf("My name is %s", name);
> printf("My name is %s and I am %d years old.", %s, %d);
>
> In other words, printf() has a variable arguement list the we
> all know.
>
> I'm trying to do this in Python...
>
> class MyPrintf(object):
>    # blah, blah
>     def myprintf(object, *arg):
>          # Here I'll have to know I NEED 2 arguments in format string
> arg[0]
>          print arg[0] % (arg[1], arg[2])
>
> name="Chris"
> age=30
> printf=MyPrintf()
> printf.myPrintf(("My name is %s and I am %d years old.", name, age)
> will of course print...
> My name is Chris and I am 42 years old.
>
> But
> printf.myPrintf(("My name is %s.", name)
> of course gives....
> Index error: list index out of range
>
> How can I generalize the print call in the myprintf() function to do this?
>
> print arg[0] % (arg[1])
> print arg[0] % (arg[1], arg[2])
> print arg[0] % (arg[1], ..., arg[n])

def printf(format, *args):
    print format % args

Although I fail to see the point in doing this. All you're doing is
trading the use of the % operator for a function call.

Cheers,
Chris

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http://blog.rebertia.com



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