newbie: precision question
Paul Watson
paul.hermeneutic at gmail.com
Sat Mar 21 04:31:26 CET 2009
On Sat, 2009-03-21 at 04:12 +0100, Lada Kugis wrote:
> I'm a newbie learning python, so forgive for, what may seem to some,
> like a stupid question.
>
> I understand the basic integer and fp type, but what I'm having a
> little trouble are the long type and infinite precision type.
>
> Also, when I do
>
> >>> math.pi - (math.sqrt(math.pi))**2.
>
> I get
>
> >>>4.4408920985006262e-016
>
> Please, could someone in just a few words, in newbie speak, explain
> why does that happen ? And what do the types actually mean ? What I
> mean, how can something have infinite precision but still not return
> zero as a result. (Btw, I always thought floating points had precision
> up to 8 significant digits, doubles 16).
>
> Nice regards
> Lada
The types used here are 'float'.
>>> math.pi
3.1415926535897931
>>> type(math.pi)
<type 'float'>
Floating point is inherently imprecise. Whatever encoding is used to
represent the number will have a finite size. That finite size puts a
limit on the precision available.
>>> 1.0/3
0.33333333333333331
>>> type(1.0/3)
<type 'float'>
Do you see how small a number the result represents
>>> print "%2.32f" % (4.4408920985006262e-016)
0.00000000000000044408920985006262
Have you tried this in any other programming languages?
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