*args question

Dave Angel davea at dejaviewphoto.com
Wed Mar 25 17:47:16 CET 2009


Try the following, to call your function yourself in this way:


def myfunction(string,sleeptime,*args):
     while 1:

         print "string is ", string
         time.sleep(sleeptime) #sleep for a specified amount of time.

f = myfunction
r = ("Thread No:1",2)
f(*r)

The key here is the   *r  syntax, which is used in a function call to 
turn a tuple (or list) into a separate set of arguments.  It's kind of 
the inverse of the *args you're already using.

DaveA

grocery_stocker wrote:
> On Mar 25, 8:28 am, Tim Chase <python.l... at tim.thechases.com> wrote:
>   
>> grocery_stocker wrote: 
>>     
<.... portions deleted ......>
> Maybe I'm missing it, but in the original code, the line had
>
> thread.start_new_thread(myfunction,("Thread No:1",2))
>
> It has a single arg  ("Thread No:1",2) versus something like
>
> thread.start_new_thread(myfunction,1, 2, ("Thread No:1",2))
>
> But
>
> def myfunction(string,sleeptime,*args):
>
> clearly takes two args. I don't get how the single arg ("Thread No:1",
> 2) in start_new_thread() gets magically converted two arges, string
> and sleeptime, before it reaches myfunction().
>
>   



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