split string at commas respecting quotes when string not in csv format
sjmachin at lexicon.net
Thu Mar 26 23:20:57 CET 2009
On Mar 27, 8:43 am, Terry Reedy <tjre... at udel.edu> wrote:
> R. David Murray wrote:
> > OK, I've got a little problem that I'd like to ask the assembled minds
> > for help with. I can write code to parse this, but I'm thinking it may
> > be possible to do it with regexes. My regex foo isn't that good, so if
> > anyone is willing to help (or offer an alternate parsing suggestion)
> > I would be greatful. (This has to be stdlib only, by the way, I
> > can't introduce any new modules into the application so pyparsing is
> > not an option.)
> > The challenge is to turn a string like this:
> > a=1,b="0234,)#($)@", k="7"
> > into this:
> > [("a", "1"), ("b", "0234,)#($)#"), ("k", "7")]
> But the starting string IS is csv format, where the values are strings
> with the format name=string.
> >>> import csv
> >>> myDialect = csv.excel
> >>> myDialect.skipinitialspace = True # needed for space before 'k'
> >>> a=list(csv.reader(['''a=1,b="0234,)#($)@", k="7"'''], myDialect))
> >>> a
> ['a=1', 'b="0234', ')#($)@"', 'k="7"']
> >>> b=[tuple(s.split('=',1)) for s in a]
> >>> b
> [('a', '1'), ('b', '"0234'), (')#($)@"',), ('k', '"7"')]
It's in the csv format that Excel accepts on input but this is
irrelevant. The output does not meet the OP's requirements; it has
taken the should-have-been-protected comma as a delimiter, and
produced FOUR elements instead of THREE ... also note '"0234' has a
leading " and ')#($)@"' has a trailing "
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