How to do this in Python?

[Luis Zarrabeitia]

On Tuesday 17 March 2009 06:04:36 pm Jim Garrison wrote:
>
> Am I missing something basic, or is this the canonical way:
>
>      with open(filename,"rb") as f:
>          buf = f.read(10000)
>          while len(buf) > 0
>              # do something....
>              buf = f.read(10000)

well, a bit more canonical would be:
           ...
           while buf:
                # do something
           ...
instead of comparing len(buf) with 0. But that's a minor detail.

One could use this: 

with open(filename, "rb") as f:
    for buf in iter(lambda: f.read(1000),''):
        do_something(buff)

but I don't really like a lambda in there. I guess one could use 
functools.partial instead, but it still looks ugly to me. Oh, well, I guess I 
also want to see the canonical way of doing it.

-- 
Luis Zarrabeitia (aka Kyrie)
Fac. de Matemática y Computación, UH.
http://profesores.matcom.uh.cu/~kyrie