KeyboardInterrupt catch does not shut down the socketserver

Gabriel Genellina gagsl-py2 at yahoo.com.ar
Sat May 16 02:01:41 CEST 2009


En Fri, 15 May 2009 09:04:05 -0300, Igor Katson escribió:
> Lawrence D'Oliveiro wrote:
>> In message <mailman.185.1242375959.8015.python-list at python.org>, Igor  
>> Katson wrote:
>>> Lawrence D'Oliveiro wrote:
>>>> In message <mailman.183.1242371089.8015.python-list at python.org>, Igor  
>>>> Katson wrote:
>>>>
>>>>> I have problems in getting a SocketServer to shutdown.
>>>>>
>>>> Do you want to do a shutdown or a close?
>>>>
>>> I want the server close the socket ...
>>>
>>
>> You want to do a close, do a close, not a shutdown  
>> <http://docs.python.org/library/socket.html>.
>>
> Shutdown implies closing the listening socket, doesn't it?

No (perhaps it should, but that is another issue). There is a
documentation bug; BaseServer.shutdown is documented as "Tells the
serve_forever() loop to stop and waits until it does." [1]
The docstring is much more explicit: """Stops the serve_forever loop.
Blocks until the loop has finished. This must be called while
serve_forever() is running in another thread, or it will deadlock."""

So, if you have a single-threaded server, *don't* use shutdown(). And, to
orderly close the listening socket, use server_close() instead. Your code
would become:

    from SocketServer import TCPServer, BaseRequestHandler

server = TCPServer(('localhost',1234), BaseRequestHandler)
try:
       server.serve_forever()
except KeyboardInterrupt:
       print "^C detected"
       pass
finally:
       print "server_close()"
       server.server_close()
print "bye"

(I've opened http://bugs.python.org/issue6031 )

[1]
http://docs.python.org/dev/library/socketserver.html?highlight=baseserver#SocketServer.BaseServer.shutdown

-- 
Gabriel Genellina




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