how to change response code in CGIHTTPServer.py

[Daniel]

Hello,

Python 2.5.2
WinXP

I'm using CGIHTTPServer.py and want to return a response code of 400
with a message in the event that the cgi script fails for some
reason.  I notice that
run_cgi(self):
executes this line of code,
self.send_response(200, "Script output follows")
which overwrites any headers that I print in my cgi.  Is there some
way to modify the response code without having to override
CGIHTTPServer.py?

Thanks,