A newbie question about some code
Dave Angel
davea at ieee.org
Tue May 19 00:22:42 EDT 2009
Jim Qiu wrote:
> Hi everyone.
> I am reading a python library code and found something i can not understand.
> Please help!
>
> class Envelope(object):
>
> def __init__(self,ta_info):
> self.ta_info = ta_info
>
>
> def writefilelist(self,ta_list,tofile):
> for filename in ta_list:
> fromfile = botslib.botsopendata(filename,
> 'rb',self.ta_info['charset'])
> shutil.copyfileobj(fromfile,tofile)
> fromfile.close()
>
> def convertfilelist(self,ta_list):
> return [botslib.botsgetabspathdata(filename) for filename in
> ta_list]
>
>
>
> class myxmlenvelop(Envelope):
> def __init__(self,ta_info,ta_list):
> ''' class for (test) xml envelope. There is no standardised
> XML-envelope!
> writes a new XML-tree; uses places-holders for XML-files to
> include; real enveloping is done by ElementTree's include'''
> self.ta_info = ta_info
> self._openoutenvelope()
> #~ self.out.put({'BOTSID':'root','xmlns:xi':"
> http://www.w3.org/2001/XInclude"}) #works, but attribute is not removed
> bij ETI.include
> self.out.put({'BOTSID':'root'})
> ta_list = self.convertfilelist(ta_list)
> for filename in ta_list:
> self.out.put({'BOTSID':'root'},{'BOTSID':'{
> http://www.w3.org/2001/XInclude}include','parse':"xml",'href':filename})
> self.out.envelopewrite(self.out.root
>
>
> Please check the blue highlighted part, I don't understand how the object
> get the property?
>
>
> Jim
>
>
Now that you tell us you want to know where the out property is coming
from, I can respond.
Clearly, you don't have the whole class listed here. Where's the
_openoutenvelop() method, for example? I'd guess it creates the out
attribute. Since it gets called from __init__(), and before the
reference to self.out, that's what makes the most sense.
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