substituting list comprehensions for map()

[Diez B. Roggisch]

Steven D'Aprano schrieb:
> On Sun, 01 Nov 2009 23:54:16 -0800, Jon P. wrote:
> 
>> I'd like to do:
>>
>> resultlist = operandlist1 + operandlist2
>>
>> where for example
>>
>> operandlist1=[1,2,3,4,5]
>> operandlist2=[5,4,3,2,1]
>>
>> and resultlist will become [6,6,6,6,6].  Using map(), I can do:
>>
>> map(lambda op1,op2: op1 + op2, operandlist1, operandlist2)
> 
> 
> If the two lists are very large, it would be faster to use this:
> 
> 
> from operator import add
> map(add, operandlist1, operandlist2)
> 
> 
>> Is there any reasonable way to do this via a list comprehension ?
> 
> [x+y for (x, y) in zip(operandlist1, operandlist2)]
> 
> If the lists are huge, you can save some temporary memory by replacing 
> zip with itertools.izip.

And even more so if one needs the results one by one - then just use a 
generator-expression.

Diez