Help resolve a syntax error on 'as' keyword (python 2.5)

[Xavier Ho]

I don't have Python 25 on my computer, but since codepad.org is using Python
2.5.1, I did a quick test:

# input
try:
    raise Exception("Mrraa!")
except Exception as msg:
    print msg

# output
t.py:3: Warning: 'as' will become a reserved keyword in Python 2.6
  Line 3
    except Exception as msg:
                      ^
SyntaxError: invalid syntax

#########

Well that's interesting. as isn't a keyword yet in Python 2.5.

This works though, and I think it fits the specification in the
documentation.

# input
try:
    raise Exception("Mrraa!")
except Exception, msg:  # Notice it's a comma
    print msg

# output
Mrraa!

##############

Hope that helps,
Xav
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