filename of calling function?

[Phlip]

Consider these two python modules:

aa.py

def a():
    print '?'

bb.py
  import aa

def bb():
  aa.a()

bb()

How do I make the print line emit the filename of bb.py? (It could be
anything.)

I am currently playing with sys.exc_info, but it seems to only emit
the stack between the raise and the except. Could be pilot error, of
course. Thanks for any help!

--
  Phlip
  http://c2.com/cgi/wiki?ZeekLand