exception due to NoneType
Ben Finney
ben+python at benfinney.id.au
Sat Nov 7 18:14:31 EST 2009
asit <lipun4u at gmail.com> writes:
> for s in users:
> print
> print "##########################################"
> try:
> print "user id : " + str(s.id)
> print "user name : " + s.name
> print "user location : " + s.location
> print "user description : " + s.description
> print "user profile image url : " + s.profile_image_url
> print "user url : " + s.url
> print "user status : " + str(s.status)
> except TypeError:
> pass
Why are you catching TypeError, only to discard it? Ignoring an error
doesn't make it go away.
The above code should rather use string formatting to interpolate the
values you want into a string for output::
import textwrap
for user in users:
print textwrap.dedent("""
##########################################
user id: %(id)s
user name: %(name)s
user location: %(location)s
user description: %(description)s
user profile image url: %(profile_image_url)s
user url: %(url)s
user status: %(status)s
""") % vars(user)
--
\ “My classmates would copulate with anything that moved, but I |
`\ never saw any reason to limit myself.” —Emo Philips |
_o__) |
Ben Finney
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